11c^2-39c=20

Solution for 11c^2-39c=20 equation:

Simplifying
11c2 + -39c = 20

Reorder the terms:
-39c + 11c2 = 20

Solving
-39c + 11c2 = 20

Solving for variable 'c'.

Reorder the terms:
-20 + -39c + 11c2 = 20 + -20

Combine like terms: 20 + -20 = 0
-20 + -39c + 11c2 = 0

Factor a trinomial.
(-5 + -11c)(4 + -1c) = 0

Subproblem 1
Set the factor '(-5 + -11c)' equal to zero and attempt to solve:

Simplifying
-5 + -11c = 0

Solving
-5 + -11c = 0

Move all terms containing c to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + -11c = 0 + 5

Combine like terms: -5 + 5 = 0
0 + -11c = 0 + 5
-11c = 0 + 5

Combine like terms: 0 + 5 = 5
-11c = 5

Divide each side by '-11'.
c = -0.4545454545

Simplifying
c = -0.4545454545
Subproblem 2
Set the factor '(4 + -1c)' equal to zero and attempt to solve:

Simplifying
4 + -1c = 0

Solving
4 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -1c = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -1c = 0 + -4
-1c = 0 + -4

Combine like terms: 0 + -4 = -4
-1c = -4

Divide each side by '-1'.
c = 4

Simplifying
c = 4
Solution
c = {-0.4545454545, 4}